Laravel框架实现的rbac权限管理操作⽰例
本⽂实例讲述了Laravel框架实现的rbac权限管理操作。分享给⼤家供⼤家参考，具体如下：
介绍：根据不同的权限，在菜单栏显⽰不同的功能，只对菜单进⾏了限制，若对路由也进⾏限制，请⾃⾏完善
1、建表（⽤户表、⾓⾊表、权限表、⽤户⾓⾊表、⾓⾊权限表）
CREATE TABLE IF NOT EXISTS mr_role
(
id int(11) PRIMARY KEY AUTO_INCREMENT COMMENT '⾃增id',
name varchar(30) NOT NULL COMMENT '⾓⾊名'
)ENGINE=innodb DEFAULT CHARSET=utf8 COMMENT='⾓⾊表';
CREATE TABLE IF NOT EXISTS mr_privilege
(
id int(11) PRIMARY KEY AUTO_INCREMENT COMMENT '⾃增id',
name varchar(30) NOT NULL COMMENT '权限名',
route varchar(50) NOT NULL COMMENT '权限所有的路由',
description varchar(100) NOT NULL COMMENT '权限的描述'
)ENGINE=innodb DEFAULT CHARSET=utf8 COMMENT='权限表';
CREATE TABLE IF NOT EXISTS mr_user_role
(
id int(11) PRIMARY KEY AUTO_INCREMENT COMMENT '⾃增id',
user_id int(11) NOT NULL COMMENT '⽤户id',
role_id int(11) NOT NULL COMMENT '⾓⾊id'
)ENGINE=innodb DEFAULT CHARSET=utf8 COMMENT='⽤户⾓⾊表';
CREATE TABLE IF NOT EXISTS mr_role_privilege
(
id int(11) PRIMARY KEY AUTO_INCREMENT COMMENT '⾃增id',
role_id int(11) NOT NULL COMMENT '⾓⾊id',
privilege_id int(11) NOT NULL COMMENT '权限id'
)ENGINE=innodb DEFAULT CHARSET=utf8 COMMENT='⾓⾊权限表';
2、在⽤户模型和⾓⾊模型中实现多对多
class User extends Model
{
protected $primaryKey = 'id';
protected $table = 'user';
sqlserver2012数据库还原
public $timestamps = false;
public $guarded = [];
public function roles()
{
return $this->belongsToMany('App\Model\Role', 'user_role', 'user_id', 'role_id')->withPivot('user_id', 'role_id');
}
}
class Role extends Model
{
protected $table = 'role';
protected $primaryKey = 'id';
public $timestamps = false;
public $guarded = [];
public function privileges()
{
return $this->belongsToMany('App\Model\Privilege', 'role_privilege', 'role_id', 'privilege_id')->withPivot(['role_id', 'privilege_id']);
}
}
3、将菜单视为公共区域，在app\Providers\AppServiceProvider.php⾥写
public function boot()
{
\View::composer('layout.slide', function($view) {
$roles_id = User::find(session('user')['id'])->roles->map(function ($role) {
return $role->id;
});  // 使⽤map，最终得到的结果$roles_id = [1, 2, ...]
$privileges = [];
foreach ($roles_id as $role) {
$privileges = array_merge($privileges, Role::find($role)->privileges->map(function ($privilege) {
return [$privilege->name, $privilege->route];
})->toArray());
}  // 得到的结果，$prpvileges = [['index/..', '列表']， ['', '']]
$view->with('privileges', $privileges);
});
}
4、菜单的实现（可以直接遍历⼀个div，我这⾥因为有不同的样式，便⽤了判断）
@foreach ($privileges as $privilege)
@if ($privilege[1] == 'key/index' && $privilege[0] == '键名列表')
<div class="slide__left__key" ><a href="{{ url('key/index') }}" rel="external nofollow" ><span class="glyphicon glyphicon-th"></span> 键名列表</a></div>
@endif
@if ($privilege[1] == 'key/create' && $privilege[0] == '添加键名')
<div class="slide__left__key"><a href="{{ url('key/create') }}" rel="external nofollow" ><span class="glyphicon glyphicon-plus"></span> 添加键名</a></div>
@endif
@if ($privilege[1] == 'project/index' && $privilege[0] == '项⽬列表')
<div class="slide__left__key" ><a href="{{ url('project/index') }}" rel="external nofollow" ><span class="glyphicon glyphicon-th-list"></span> 项⽬列表</a></div>      @endif
@if ($privilege[1] == 'project/create' && $privilege[0] == '添加项⽬')
<div class="slide__left__key"><a href="{{ url('project/create') }}" rel="external nofollow" ><span class="glyphicon glyphicon-edit"></span> 添加项⽬</a></div>
@endif
@if ($privilege[1] == 'user/index' && $privilege[0] == '⽤户列表')
<div class="slide__left__key" ><a href="{{ url('user/index') }}" rel="external nofollow" ><span class="glyphicon glyphicon-th-large"></span> ⽤户列表</a></div>      @endif
@if ($privilege[1] == 'user/create' && $privilege[0] == '添加⽤户')
<div class="slide__left__key"><a href="{{ url('user/create') }}" rel="external nofollow" ><span class="glyphicon glyphicon-plus-sign"></span> 添加⽤户</a></div>
@endif
@endforeach
更多关于Laravel相关内容感兴趣的读者可查看本站专题：《》、《》、《》、《》及《》
希望本⽂所述对⼤家基于Laravel框架的PHP程序设计有所帮助。