linuxc语⾔round函数,c语⾔函数的参数传递⽰例_lround（）函
数以及C++中。。。
c语⾔ 函数的参数传递⽰例
C ++ lround()函数 (C++ lround() function)
lround() function is a library function of cmath header, it is used to round the given value and casts to a long integer, it accepts a number and returns the integer (long int) value that is nearest to the number (with halfway cases).
lround()函数是cmath标头的库函数，⽤于舍⼊给定值并将其转换为长整数，它接受⼀个数字并返回最接近该数字的整数(长int)值(有中途情况) )。
Syntax of lround() function:
lround()函数的语法：
lround(x);
Parameter(s): x – is the number to round nearest to zero with halfway cases.
参数： x –是中途取整的数字，最接近零。
Return value: long int – it returns long int type value that is the rounded value of the number x.
返回值： long int –返回long int类型值，该值是数字x的舍⼊值。
Example:
例：
Input:
float x = 2.3;
Function call:
lround(x);
Output:
2
Input:
float x = 2.8;round函数有几个参数
Function call:
lround(x);
Output:
3
C ++代码演⽰lround()函数的⽰例 (C++ code to demonstrate the example of lround() function)
// C++ code to demonstrate the example of
// lround() function
#include
#include
using namespace std;
// main() section
int main()
{
float x;
x = 15.3;
cout<
x = 15.5;
cout<
x = 15.8;
cout<
x = -15.3;
cout<
x = -15.5;
cout<
x = -15.8;
cout<
return 0;
}
Output
输出量
lround(15.3): 15
lround(15.5): 16
lround(15.8): 16
lround(-15.3): -15 lround(-15.5): -16 lround(-15.8): -16
c语⾔ 函数的参数传递⽰例