Python实现过迷宫⼩游戏⽰例详解
⽬录
前⾔
开发⼯具
环境搭建
原理简介
主要代码
前⾔
今天为⼤家带来解闷⽤的过迷宫⼩游戏分享给⼤家好了。让我们愉快地开始吧~
开发⼯具
Python版本： 3.6.4
相关模块：
pygame模块；
以及⼀些Python⾃带的模块。
环境搭建
安装Python并添加到环境变量，pip安装需要的相关模块即可。
原理简介
游戏规则：
玩家通过↑↓←→键控制主⾓⾏动，使主⾓从出发点(左上⾓)绕出迷宫，到达终点(右下⾓)即为游戏胜利。
逐步实现：
⾸先，当然是创建迷宫啦，为了⽅便，这⾥采⽤随机⽣成迷宫的⽅式(⼈⼯设计真的费眼睛，弄到⼀半不想弄了，有兴趣的可以⾃⾏
尝试。)。思路其实很简单，就是把游戏界⾯划分成多个cell，类似这样⼦：
然后设计算法遍历所有的cell，每个被遍历到的cell在某⼏个随机的⽅向上打开⼀堵墙(就是去掉分割cell的线条)就ok啦~
主要代码
'''随机⽣成迷宫类'''
class RandomMaze():
def __init__(self, maze_size, block_size, border_size, **kwargs):
self.block_size = block_size
self.border_size = border_size
self.maze_size = maze_size
self.blocks_list = ateMaze(maze_size, block_size, border_size)
self.font = pygame.font.SysFont('Consolas', 15)
'''画到屏幕上'''
def draw(self, screen):
for row in range(self.maze_size[0]):
for col in range(self.maze_size[1]):
self.blocks_list[row][col].draw(screen)
# 起点和终点标志
showText(screen, self.font, 'S', (255, 0, 0), (self.border_size[0]-10, self.border_size[1]))
showText(screen, self.font, 'D', (255, 0, 0), (self.border_size[0]+(self.maze_size[1]-1)*self.block_size, self.border_size[1]+self.maze_size[0]*self.block_size+5)) '''创建迷宫'''
@staticmethod
def createMaze(maze_size, block_size, border_size):
def nextBlock(block_now, blocks_list):
directions = ['top', 'bottom', 'left', 'right']
blocks_around = dict(zip(directions, [None]*4))
block_next = None
count = 0
# 查看上边block
if dinate[1]-1 >= 0:
block_now_top = blocks_list[dinate[1]-1][dinate[0]]
if not block_now_top.is_visited:
blocks_around['top'] = block_now_top
count += 1
# 查看下边block
if dinate[1]+1 < maze_size[0]:
block_now_bottom = blocks_list[dinate[1]+1][dinate[0]]
if not block_now_bottom.is_visited:
blocks_around['bottom'] = block_now_bottom
count += 1
# 查看左边block
if dinate[0]-1 >= 0:
block_now_left = blocks_list[dinate[1]][dinate[0]-1]
if not block_now_left.is_visited:
blocks_around['left'] = block_now_left
count += 1
# 查看右边block
if dinate[0]+1 < maze_size[1]:
block_now_right = blocks_list[dinate[1]][dinate[0]+1]
if not block_now_right.is_visited:
blocks_around['right'] = block_now_right
count += 1
if count > 0:
while True:
direction = random.choice(directions)
if (direction):
block_next = (direction)
if direction == 'top':
block_next.has_walls[1] = False
block_now.has_walls[0] = False
elif direction == 'bottom':
block_next.has_walls[0] = False
block_now.has_walls[1] = False
elif direction == 'left':
block_next.has_walls[3] = False
block_now.has_walls[2] = False
elif direction == 'right':
block_next.has_walls[2] = False
block_now.has_walls[3] = False
break
return block_next
blocks_list = [[Block([col, row], block_size, border_size) for col in range(maze_size[1])] for row in range(maze_size[0])]
block_now = blocks_list[0][0]
records = []
while True:
if block_now:
if not block_now.is_visited:
block_now.is_visited = True
records.append(block_now)
block_now = nextBlock(block_now, blocks_list)
else:
block_now = records.pop()
if len(records) == 0:
break
return blocks_list
接下来就是定义⾓⾊类啦，⾓⾊类需要根据⽤户的操作进⾏上下左右的移动，同时，保证移动是不能跨越墙的就OK了~具体⽽⾔，代码实现如下：
'''定义hero'''
class Hero(pygame.sprite.Sprite):
def __init__(self, imagepath, coordinate, block_size, border_size, **kwargs):
pygame.sprite.Sprite.__init__(self)
self.image = pygame.image.load(imagepath)
self.image = ansform.scale(self.image, (block_size, block_size))
< = _rect()
self.block_size = block_size
self.border_size = border_size
'''移动'''
def move(self, direction, maze):
blocks_list = maze.blocks_list
if direction == 'up':
if blocks_dinate[1]][dinate[0]].has_walls[0]:
return False
else:
return True
elif direction == 'down':
if blocks_dinate[1]][dinate[0]].has_walls[1]:
return False
else:
return True
elif direction == 'left':
if blocks_dinate[1]][dinate[0]].has_walls[2]:
return False
else:
return True
elif direction == 'right':
if blocks_dinate[1]][dinate[0]].has_walls[3]:
return False
else:
return True
else:
raise ValueError('Unsupport direction <%s> ve...' % direction)
'''绑定到屏幕'''
def draw(self, screen):
screen.blit(self.image, )
最后，就是写下游戏主循环，这个其实也很简单，只要每次载⼊⼀个随机⽣成的迷宫地图和实例化⼀个主⾓，然后不断进⾏按键检测，并根据按键检测的结果移动主⾓，最后根据⾏动结果更新界⾯数据就OK了~当然，若主⾓到达了终点，则进⼊关卡切换界⾯。
具体⽽⾔，代码实现如下：
'''主函数'''
def main(cfg):
# 初始化
pygame.init()
pygame.mixer.init()
pygame.font.init()
pygame.mixer.music.load(cfg.BGMPATH)
pygame.mixer.music.play(-1, 0.0)
screen = pygame.display.set_mode(cfg.SCREENSIZE)
pygame.display.set_caption('Maze - : Charles的⽪卡丘')
font = pygame.font.SysFont('Consolas', 15)
# 开始界⾯
Interface(screen, cfg, 'game_start')
# 记录关卡数
num_levels = 0
# 记录最少⽤了多少步通关
best_scores = 'None'
# 关卡循环切换
while True:
python可以做什么游戏num_levels += 1
clock = pygame.time.Clock()
screen = pygame.display.set_mode(cfg.SCREENSIZE)
# --随机⽣成关卡地图
maze_now = RandomMaze(cfg.MAZESIZE, cfg.BLOCKSIZE, cfg.BORDERSIZE)
# --⽣成hero
hero_now = Hero(cfg.HEROPICPATH, [0, 0], cfg.BLOCKSIZE, cfg.BORDERSIZE)
# --统计步数
num_steps = 0
# --关卡内主循环
while True:
dt = clock.tick(cfg.FPS)
screen.fill((255, 255, 255))
is_move = False
# ----↑↓←→控制hero
for event in ():
pe == pygame.QUIT:
pygame.quit()
pe == pygame.KEYDOWN:
if event.key == pygame.K_UP:
is_move = ve('up', maze_now)
elif event.key == pygame.K_DOWN:
is_move = ve('down', maze_now)
elif event.key == pygame.K_LEFT:
is_move = ve('left', maze_now)
elif event.key == pygame.K_RIGHT:
is_move = ve('right', maze_now)
num_steps += int(is_move)
hero_now.draw(screen)
maze_now.draw(screen)
# ----显⽰⼀些信息
showText(screen, font, 'LEVELDONE: %d' % num_levels, (255, 0, 0), (10, 10))
showText(screen, font, 'BESTSCORE: %s' % best_scores, (255, 0, 0), (210, 10))
showText(screen, font, 'USEDSTEPS: %s' % num_steps, (255, 0, 0), (410, 10))
showText(screen, font, 'S: your starting point D: your destination', (255, 0, 0), (10, 600))
# ----判断游戏是否胜利
if (dinate[0] == cfg.MAZESIZE[1] - 1) and (dinate[1] == cfg.MAZESIZE[0] - 1):
break
pygame.display.update()
# 更新最优成绩
if best_scores == 'None':
best_scores = num_steps
else:
if best_scores > num_steps:
best_scores = num_steps
# 关卡切换
Interface(screen, cfg, mode='game_switch')
到此这篇关于Python实现过迷宫⼩游戏⽰例详解的⽂章就介绍到这了，更多相关Python过迷宫⼩游戏内容请搜索以前的⽂章或继续浏览下⾯的相关⽂章希望⼤家以后多多⽀持！
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